find the length of the diagonal of rectangle whose length is 8 cm and width is 6 CM
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Answered by
1
Answer:
By Pythagoras theorem,
l² + b² = h²
So, h² = 8² + 6²
h² = 64 + 36
h² = 100
So, h=10
Answered by
0
Answer:
10cm
Step-by-step explanation:
Length = 8cm
Breadth = 6cm
Let diagonal be xcm.
Now,
8^2 + 6^2 = x^2
=) 64 + 36 = x^2
=) 100 = x^2
=) 10^2 = x^2
=) 10 = x
Hence, the diagonal is 10cm.
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