Find the length of the diagonals of a rectangle whose sides are 4cm and 3cm
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Answered by
53
Length = 4 cm
Width = 3 cm
Diagonal =
Diagonal = root 4^2 + 3^2
= root 16 + 9
= root 25
= 5 cm
Width = 3 cm
Diagonal =
Diagonal = root 4^2 + 3^2
= root 16 + 9
= root 25
= 5 cm
diro:
thank you for helping
Answered by
22
Now we know that Rectangle can be divided into two right angled triangles let us take one of the triangles as ABC and now
Apply Pythagoras theorem
(AC)^2=(AB)^2+(BC)^2
AC=_/25=5cm
Ans:-Diagonals of a rectangle are 5cm (diagonals of a rectangle are equal.
HOPE THIS ANSWER HELPS PLS MARK IT AS THE BRAINLIEST ANSWER
Apply Pythagoras theorem
(AC)^2=(AB)^2+(BC)^2
AC=_/25=5cm
Ans:-Diagonals of a rectangle are 5cm (diagonals of a rectangle are equal.
HOPE THIS ANSWER HELPS PLS MARK IT AS THE BRAINLIEST ANSWER
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