Question

find the length of the diagonals of a rectangle whose sides are 24cm and 10cm.​

Answer 1

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Length of the rectangle = 24cm
• Breadth = 10cm

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Diagonal = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

$\sf{\red{\boxed{\bold{Diagonal = \sqrt{ length^2 + breadth^2}}}}}$

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$: \implies\: \sf{\bold{ Diagonal = \sqrt{ 24^2 + 10^2} }}$

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$: \implies\: \sf{\bold{ Diagonal = \sqrt{ 576 + 100} }}$

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$: \implies\: \sf{\bold{ Diagonal = \sqrt{ 676 } }}$

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$: \implies\: \sf{\bold{ Diagonal = \sqrt{ 2\times 2\times 13\times 13} }}$

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$: \implies\: \sf{\bold{ Diagonal = 2 \times 13}}$

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$: \implies\: \sf{\bold{ Diagonal = 26cm }}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Diagonal of the rectangle = 26cm

Answer 2

Answer:

d= w*+ l* = 10* + 24* = 26cm

Step-by-step explanation:

I used square instead *