Question

Find the length of the diameter of the circle having centre at (-3, 6) and passing through P(1, 3)

Answer 1

$\large\text{\underline{Start!}}$

$\green{\text{Diameter and Radius}}$

• Diameter is the longest chord, which passes through the center of the circle. We know that the diameter is two times the length of the radius.

$\purple{\hookrightarrow\text{(Diameter)}=2\times\text{(Radius)}}$

$\red{\text{Equation of Circle}}$

The equation of a circle is $\purple{(x-a)^{2}+(y-b)^{2}=r^{2}}$

$\red{\text{Distance Between Two Points}}$

The distance between two points is known as $\purple{\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}}$

$\large\text{\underline{Solution}}$

$O(-3,6)$ and $P(1,3)$ are the coordinates which distance can be found by joining two points. One of the points $O$ is the center of the circle and $P$ is on the circle, and the distance is called the radius.

$\text{(Distance)}$

$=\sqrt{(-3-1)^{2}+(6-3)^{2}}$

$=\sqrt{4^{2}+3^{2}}$

$=\sqrt{25}$

$=5$

Since the diameter is two times the radius, the diameter is $10\text{ units}$.

$\large\text{\underline{Conclusion}}$

So, the length of the diameter is $10\text{ units}$.

Answer 2

Answer:

Heya bhai

Aapki ig id mil skti hai..??