Question

Find the length of the height of an equilateral triangle of side 24cm. [Take]
$\sqrt{3} = 1.73$

Answer 1

Heya !!!

This is your answer.....

Given :-

Side, a = 24 cm.
We know that area of equilateral triangle is ....

A = √3/4 × a².

So.....
$area \: = \: \frac{ \sqrt{3} }{4} \times 24 \times 24 \\ = \sqrt{3} \times 6 \times 24 \\ = 1.73 \times 144 \\ = 249.12 \: {cm}^{2}$

Hence, the area of equilateral triangle is 249.12 cm².

Now...........

We know that area of triangle is also equal to
...1/2 × Base × height.

Base = 24 cm.
and area = 249.12 cm².

Area = 1/2 × bh.
$249.12\times 2 = 24 \times h \\ = > h = \frac{249.12 \times 2}{24} \\ = > h = 20.76 \: cm$
Hence the height of equilateral triangle is 20.76 cm.

Hope it helps

Answer 2

the answer will.be 20.76( estimately)