Math, asked by rani7913, 1 month ago

find the length of the hypotenuse in a right angled triangle
a) a=12cm ,b=9cm
b) a=8cm , b=15cm

explain​

Answers

Answered by Anonymous
2

CONCEPT :-

♦ Pythagoras Theorem :-

In a right angle triangle , sum of square of base and height is equal to square of hypotenuse.

Hypotenuse ² = Base² + Height²

SOLUTION :-

a) a = 12cm , b = 9cm

Here , we are given height and base of the right angled triangle. We have to find Hypotenuse.

→ Hypotenuse² = 12² + 9²

→ Hypotenuse² = 144 + 81

→ Hypotenuse² = 225

→ Hypotenuse = √225

Hypotenuse = 15cm

Hence , Hypotenuse is 15cm.

________________________

b) a = 8cm , b = 15cm

Similarly , base and height are given as 8cm and 15cm. We have to find Hypotenuse.

→ Hypotenuse² = 8² + 15²

→ Hypotenuse² = 64 + 225

→ Hypotenuse² = 289

→ Hypotenuse = √289

Hypotenuse = 17cm

Hence , Hypotenuse is 17cm.

Answered by Anonymous
1

\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}Brainly Song

(Remix)

Ooh ooh, oh, ooh ooh

Oh oh oh oh ooh ooh, oh

Oh oh oh oh oh oh

Ooh ooh, oh, ooh ooh

Oh oh oh oh ooh ooh, oh

We're no strangers to Brainly

You know the book, and so do I

A number 6 is what I’m thinking of

You wouldn't get this from any other mates

I just wanna tell you how I'm feeling

Gotta make you understand

Never gonna follow that brainly

Never gonna shoot those mates

Never gonna take care of our business

And...

Relax on the pedal, dude!

Ayy! Look OUUUU-, OUUUU-, OU-

OUUUU-, OUUUU-, OU- OU- OU- OU- OU-

Ooooohhhhhhh

You okay, mane?

Nah, man

This was a mistake\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}\Huge{{\texttt{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}\huge{❥}\:{\mathtt{{\purple{\boxed{\tt{\pink{\red{A}\pink{n}\orange{s}\green{w}\blue{e}\purple{r᭄}}}}}}}}❥

 \bold{Let  \: the \:  number \:  be \:  x}

 \bf{According \:  to  \: the \:  question}

 \bold{\frac{2}{3}x \:  =  \frac{1}{3}x + 3 }

 \bold{ \frac{2}{3} x -  \frac{1}{3}x = 3 }

 \bold{ \frac{2x - x}{3}  = 3}

 \bold \green{x = 9}

Similar questions