Question

Find the length of the hypotenuse of a right angled triangle whose Base=12cm and Height =5cm 4M

Answer 1

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Find the length of the hypotenuse of a right angled triangle whose Base=12cm and Height =5cm 4M

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According To The Question, We need to find the Hypotenuse↷

We'll solve by Pythagoras Theorum↷

Which states:-

• AC² = AB² + BC²
• In which AC is the Hypotenuse and AB, BC are the two sides of the 'Right-Angled Triangle'.

Given Values↷

✳ Base = 12cm

✳ Height = 5cm

Let the Base and Height be AB and BC. Then↷

$= > \: AC² = {5}^{2} + {12}^{2} \\ = > AC² = 25 \: + 144 \\ = > AC² = 169 \\ = > AC = \sqrt{169} \\ = > AC = 13cm$

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∴ Hence, The Length Of The Hypotenuse = 13cm

Answer 2

✳ Base = 12cm

✳ Height = 5cm

Let the Base and Height be AB and BC. Then↷

\begin{gathered} = > \: AC² = {5}^{2} + {12}^{2} \\ = > AC² = 25 \: + 144 \\ = > AC² = 169 \\ = > AC = \sqrt{169} \\ = > AC = 13cm\end{gathered}

=>AC²=5

2

+12

2

=>AC²=25+144

=>AC²=169

=>AC=

169

=>AC=13cm

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⛤FinalAnswer:−

∴ Hence, The Length Of The Hypotenuse = 13cm