Question

*Find the length of the hypotenuse of a right angled triangle if remaining sides are 10 cm and 24 cm.*

1️⃣ 26 cm
2️⃣ 28 cm
3️⃣ 30 cm
4️⃣ 32 cm​

Answer 1

Given :

Base of right angle triangle = 10cm

Perpendicular of right triangle = 24cm

To find :

Hypotenuse of right triangle = ?

Solution :

Using the pythagoras theorem that is,

» Pythagoras theorem states that In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.[tex][/tex]

Formula : H² = P² + B².

Where,

• H is the Hypotenuse.
• P is the Perpendicular.
• B is the Base.

By substituting all the given values in the formula,

➙ H² = (24)² + (10)²

➙ H² = 576 + (10)²

➙ H² = 576 + 100

➙ H² = 676

➙ H = √676

➙ H = 26

Hence, option (1) 26cm is the length of the hypotenuse of a right angled triangle.

Answer 2

Answer:

Given :-

• A right angled triangle if remaining sides are 10 cm and 24 cm.

To Find :-

• What is the length of the hypotenuse of a right angled triangle.

Formula Used :-

$\clubsuit$ Pythagoras Theorem :

$\longmapsto \sf\boxed{\bold{\pink{{(Hypotenuse)}^{2} =\: {(Perpendicular)}^{2} + {(Base)}^{2}}}}$

Solution :-

Given :

• Base = 10 cm
• Perpendicular = 24 cm

According to the question by using the formula we get,

$\implies \sf {(Hypotenuse)}^{2} =\: {(24)}^{2} + {(10)}^{2}$

$\implies \sf {(Hypotenuse)}^{2} =\: 24 \times 24 + 10 \times 10$

$\implies \sf {(Hypotenuse)}^{2} =\: 576 + 100$

$\implies \sf {(Hypotenuse)}^{2} =\: 676$

$\implies \sf Hypotenuse=\: \sqrt{676}$

$\implies\sf\bold{\red{Hypotenuse =\: 26\: cm}}$

$\therefore$ The length of the hypotenuse of a right angled triangle is 26 cm .

Hence, the correct options is option no (1) 26 cm .