Find the length of the hypotenuse of a right angled triangle if remaining sides are 9 cm and 12 cm. Solve the following example.
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Answered by
3
by using pythogoras theorem we get
9x9 + 12x12 = hypotenuse squared
81 +144 = hypot. squared
so 15 cm is the hypotenuse
hope it helps...
9x9 + 12x12 = hypotenuse squared
81 +144 = hypot. squared
so 15 cm is the hypotenuse
hope it helps...
Answered by
1
Perpendicular,P = 9cm
Base, B= 12cm
Hypotenuse,H = √(9^2+12^2)
H = √(81 + 144)
H = √225
H = 15cm
Base, B= 12cm
Hypotenuse,H = √(9^2+12^2)
H = √(81 + 144)
H = √225
H = 15cm
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