find the length of the hypotenuse of a square whose side is 16cm
Answers
Answered by
103
All sides of square are equal =16cm
vertex angle 90degree
so it's one diagonal is equal to hypotenuse
We find hypotenuse by Pythagoras theory
H^2=P^2+B^2
H^2=16^2+16^2
H^2=256+256
H^2=512
H=√512
H=16√2
H=22.62cm
vertex angle 90degree
so it's one diagonal is equal to hypotenuse
We find hypotenuse by Pythagoras theory
H^2=P^2+B^2
H^2=16^2+16^2
H^2=256+256
H^2=512
H=√512
H=16√2
H=22.62cm
ushukothari:
Can u tell me what is the meaning of this(^)
because I don't know
It means rise to the power
Answered by
32
Answer:
Step-by-step explanation:
The square forms a right angled triangle with sides a, b and c.
a and b are the two sort sides.
c is the hypotenuse.
Now a = b = 16cm
By pythagoras theorem :
a^2 + b^2 = c^2
c^2 = (256 + 256)
= 512
c = square root of 512
= 22.63
= 22.63 cm
i think the answer is 22.62
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