Find the length of the hypotenuse of a square whose side is 16 cm
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Answered by
18
All sides of square are equal =16cm
vertex angle 90degree
so it's one diagonal is equal to hypotenuse
By Pythagoras theorem
H^2=a^2+b^2
H^2=16^2+16^2
H^2=256+256
H^2=512
H=√512
H=16√2
H=22.62
Hope it helps u.
Answered by
4
Answer:
Step-by-step explanation:
H^2=a^2+b^2
H^2=16^2+16^2
H^2=256+256
H^2=512
H=√512
H=16√2
H=22.62
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