Find the length of the hypotenuse of each of the triangles. Round each solution to the nearest whole number.
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3.Pythagoras theorem AC²=AB²+BC²
So let's consider the given triangle as ABC
Here AC²=?
AB²=6 and BC²=8
so AC²=(6)²+(8)²
=36+64
AC²=100
AC=√100=10
4.Pythagoras theorem AC²=AB²+BC²
So let's consider the given triangle as ABC
Here AC²=?
AB²=30 and BC²=40
So AC²=(30)²+(40)²
=900+1600
AC²=2500
AC=√2500=50
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3) =
x^{2} = 100
x = 10
∴ Hypotenus = 10
4)
x^{2} = 2500
x = 50
∴ Hypotenus = 50
Hope it helps and plss mark Brainliest
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