Math, asked by 277713, 9 months ago

Find the length of the hypotenuse of each of the triangles. Round each solution to the nearest whole number.

Attachments:

Answers

Answered by madhulathahoney2026
0

Answer:

3.Pythagoras theorem AC²=AB²+BC²

So let's consider the given triangle as ABC

Here AC²=?

AB²=6 and BC²=8

so AC²=(6)²+(8)²

=36+64

AC²=100

AC=√100=10

4.Pythagoras theorem AC²=AB²+BC²

So let's consider the given triangle as ABC

Here AC²=?

AB²=30 and BC²=40

So AC²=(30)²+(40)²

=900+1600

AC²=2500

AC=√2500=50

plz mark it as the brainliest answer

Answered by zayedkhan0906
0

3) x^{2} = 6^{2} + 8^{2}

x^{2} = 100

x = 10

∴ Hypotenus = 10

4) x^{2} = 30^{2} + 40^{2}

x^{2} = 2500

x = 50

∴ Hypotenus = 50

Hope it helps and plss mark Brainliest

Similar questions