Find the length of the hypotenuse of the right angled triangle ABC = where AB =3m ,BC =4m and B=90°
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9
AC^2 = ab^2 + bc^2
= 3^2 + 4^2
= 9+ 16
ac^2=25
ac=5
= 3^2 + 4^2
= 9+ 16
ac^2=25
ac=5
anjali1479:
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Answered by
7
AC=square root of(3)^2+(4)^2
=square root of 9+16
=sq root of 25
=5
=square root of 9+16
=sq root of 25
=5
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