Question

Find the length of the largest pole that can be placed in a room of dimensions 12m×4m×3m.

Answer 1

The largest pole that could be fit in a room will be its diagonal,
$diagonal \: of \: cuboid = \sqrt{ {l}^{2} + {h}^{2} + {b}^{2} }$
$diagonal = \sqrt{ {12}^{2} + {4}^{2} + {3}^{2} }$
$diagonal = \sqrt{144 + 16 + 9}$
$diagonal = \sqrt{169}$
$diagonal \: = 13m$

So the length of the largest pole in the room will be 13m!!
Hope it Helps!!

Answer 2

length of the largest pole =length of its diagonal =under root length square + breadth square + height square = whole square root of12^2+4^2+3^2=underroot 169cm^2=13cm
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