Find the length of the line AB formed by joining the points A acos thita,0) and
B(0,asin thita).
Answers
Answered by
0
Answer:
Given the point A(cosθ+bsinθ,0),(0,asinθ−bcosθ)
By distance formula,
The distance of AB=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
=
[0−(acosθ+bsinθ)
2
+(asinθ−bcosθ)−0]
2
=
a
2
cos
2
θ+2abcosθsinθ+a
2
sin
2
θ+b
2
cos
2
θ−2absinθcosθ
=
(a
2
+b
2
)cos
2
θ+(a
2
+b
2
)sin
2
θ
=
a
2
+b
2
[∵cos
2
θ+sin
2
θ=1]
Answered by
3
Answer:
A
Step-by-step explanation:
A = (Acosthitha,0)
B = (0,Asinthita)
Distance between two points =
√[(x2 - x1)^2 + (y2-y1)^2
So for this line
= √[(0 - Acosthitha)^2 + (Acosthita - 0)^2]
= √[( - Acosthita)^2 + (Asinthita)^2]
= √[(A^2)(cos^2thita) + (A^2)(sin^2thita)]
= √{(A^2)[cos^2thita + sin^2thita]}
= √{(A^2)[1]}
= √(A^2)
= A
Similar questions