Question

find the length of the longest pencil which can be placed in a geometrical instruments box measuring 16 cm by 8 cm by 2 cm​

Answer 1

Answer:

18cm

Step-by-step explanation:

Answer = $\sqrt{16^{2}+8^{2}+2^{2}} =\sqrt{256+64+4} =\sqrt{324} =18cm$

Answer 2

Step-by-step explanation:

Apply Pythagoras Theorem

Consider the diagonal as the longest side where largest pencil could be kept .

therefore

Diagonal of a Cuboid Will be equal to its hypotenuse

(√2 square + 16 square + 8 square )