Question

Find the length of the longest pole that can be kept in a room of 10m 8m 5m

Answer 1

let l=10m
b=8m
h=5m
diagonal , the length of the longest rod
=
$\sqrt(l2 + b2 + h2 )$
$= \sqrt{10 \times10 + 8 \times 8 + 5 \times 5}$
$= \sqrt{100 + 64 + 25}$
$= \sqrt{189}$
=13.74m(approx)

Answer 2

Step-by-step explanation:

THE LENGTH OF THE LONGEST POLE IS THE DIAGONAL

DIAGONAL=✓(L^2 + B^2 + H^2)

=✓(10^2+8^2+5^2)

=✓100+64+25

=✓189

=13.7

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