Question

Find the length of the longest pole that can be put in a room of dimensions 11m × 10m × 6m. Please answer this Question ASAP. I will mark first one Brainliest!!!

Answer 1

$the \: correct \: answer \: is \: 660$

$hope \: it \: helps \: u \\ mrk \: me \: s \: brainlist \\ tysm$

Answer 2

Answer:

16 m approx

Step-by-step explanation:

The longest pole in the room can only be a hypotenuse of the face of the cuboid. So the formula devised for this is $\sqrt{x^2 + y^2 + z^2$

In this case, x = 11, y = 10 and z = 6.

So $\sqrt{11^2 + 10^2 + 6^2} = \sqrt{121 + 100 + 36} = \sqrt{257} = 16.03 = 16 m$

Therefore, the answer is 16 m approx