Question

Find the length of the longest rod that can be place in a room of dimension 8m,10m, and 6m

Answer 1

The diagonal will be the largest rod
=> l = whole root ( l^2+ b^2 +h^2)
L= whole root ( 64 + 36 + 100 )
L = whole root ( 200 )
L= 10root 2
L= 10 x 1.732 m
L= 17.32m (approx)

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Answer 2

Answer:

10√2 m

Step-by-step explanation:

Given length l = 8 m

breadth b = 10 m and height h = 6 m

Longest rod that can be placed in a room is nothing but its diagonal.

Length of diagonal of a cuboid = √(8 + 10 + 6)

Length of longest rod = √(64+100+36) m

= √200 m

= √100x2 m

= 10√2 m