find the length of the longest rod that can be placed in a room of dimensions 8m ,10m and 6m
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diangonal =√8^2+10^2+6^2=√200=10√2cm
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Let Length of rode be x
So, x=√l^2+b^2+r^2
x=√8^2+10^2+6^2
x=√64+100+36
x=√200
x=10√2 m
So Length of rod=10√2 m
So, x=√l^2+b^2+r^2
x=√8^2+10^2+6^2
x=√64+100+36
x=√200
x=10√2 m
So Length of rod=10√2 m
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