Question

Find the length of the longest rod that can be put in a room of 10m×10m×5m dimensions.

Answer 1

Cuboidal :  A figure which is surrounded by six  rectangular surfaces is called cuboid.

SOLUTION :
Given:
Length of a room(l) = 10 m
Breadth of a room(b) = 10 m
Height of a room(h) = 5m

The length of the longest rod is the diagonal of the room.
So, We have to find the diagonal of the cuboid.

Diagonal of a cuboid = √ (l)² + (b)² + (h)²

Diagonal of a cuboid = √ (10)² + (10)² + (5)²
Diagonal of a cuboid = √ 100 + 100 + 25
Diagonal of a cuboid = √ 225
Diagonal of a cuboid = √ 15 × 15  = 15 m

Hence , The length of the longest rod can be put in a room is 15 m.

HOPE THIS WILL HELP YOU...

Answer 2

Hey mate...


Here's your answer..

________________________________


$length \: of \: biggest \: rod = diagonal \: of \: cuboid \\ = \sqrt({l ^{2} } + {b}^{2} + {h}^{2} ) \\ = \sqrt{10 \times 10 + 10 \times 10 + 5 \times 5} \\ = \sqrt{100 + 100 + 25} \\ = \sqrt{225} \\ = 15cm$
________________________________

HOPE IT HELPS..

@Rêyaañ11