Find the length of the longest rod that can be put in a room of dimension 6m*4m*3m
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Hello
solution of your question is
d² = l² + b² + h²
d² = 36 +16 +9
d² =61
d=√61
d=7.81 m
solution of your question is
d² = l² + b² + h²
d² = 36 +16 +9
d² =61
d=√61
d=7.81 m
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