Find the length of the median drawn through A on BC of a triangle ABC whose vertices are A(7,-3), B(5 3), C(3, -1).
Class 10_CBSE_Co-ordinate Geometry
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Answer:
- 5 units
- 5 units
- √10 units
Step-by-step explanation:
Given
- Vertices :
- A (7 , -3)
- B (5 , 3)
- C (3 , -1)
To find
- Length of the medians of a triangle.
Solution
⇛ Let D, E, F be the mid points of BC, CA and AB respectively.
⇛ Then, the co-ordinates of these points are :
- D = (5 + 3/2) , (3 + (-1)/2)
- E = (3 + 7/2) , (-1 -3/2)
- F = (7 + 5/2) , (-3 + 3/2)
ie,, D(4 , 1) , E( 5 , -2) and F( 6 , 0)
Using distance formula :
↪ AD = √(7-4)² + (3-1)² = 5 units
↪ BE = √(5-5)² + (3-(-2)² = 5 units
↪ CF = √(6-3)² + (0-(-1)² = √10 units
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