Find the length of the median through the vertex A(5, 1) drawn to the triangle ABC where other two vertices are B(1, 5) and C(-3, -1)
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19
Answer:
root 37
Step-by-step explanation:
let abc be the triangle
a=(5,1), b=(1,5), c=(-3,-1)
median drawn through a to bc will intersect bc at point d
vertices of d=(1-3/2 , 5-1/2) as d will be the mid point of bc
[d=(x₁+x₂/2 , y₁+y₂/2)]
d=(-2/2 , 4/2)
d=(-1,2)
length of ad= √(x₂-x₁₎²+₍y₂-y₁₎² a(5,1) d(-1,2)
ad=√(-1-5)²+(2-1)²=√(-6)²+1
=√36+1
√37 ans
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