Question

Find the length of the medians of the triangle whose vertices are (1, -1) and( 0, 4) and(- 5, 3).
HALA MADRID !!!

Answer 1

Step-by-step explanation:

Hola frnd

$let \: abc \: be \: your \: triangle$

$let = >$

A = (1,-1) = (x1,y1)

B = (0,4) = (x2,y2)

C = (-5,3) = (x3,y3)

Median touches side it it's mid pt

Let P be mid pt of AB

Q be mid pt of BC

R be mid pt of AC

For P

$x = \frac{1}{2} \: \: \: \: and \: \: \: \: y = \frac{3}{2}$

$so \: lenght \: of \: first \: median \: = >$

D = √(-5 - 1/2)^2 +(3 - 3/2)^2

D = √(-11/2) ^2 + (3/2)^2

D = √121/4 + 9/4

D = √130/4

Length of first median is √130/4

similarly u can find all of them

Hope it helps uh!!