find the length of the medians of the triangle whose vertices are (-1,3), (1,-1) and (5,1).
Answers
Answered by
40
the question is not clear,
so, i take A(-1, 3), B(1, -1), C(5, 1) and find the length of median through vertex C
In a triangle of ABC. Let the midpoint be D which lies in between B and C
So, D = (1+5/2, -1+1/2) = (3,0)
So, Length of median = root of [(-1-3)^2 + (3-0)^2]
= root of [(4)^2 + (3)^2]
= root [16 + 9]
= root 25
= 5
Hope this helps!
so, i take A(-1, 3), B(1, -1), C(5, 1) and find the length of median through vertex C
In a triangle of ABC. Let the midpoint be D which lies in between B and C
So, D = (1+5/2, -1+1/2) = (3,0)
So, Length of median = root of [(-1-3)^2 + (3-0)^2]
= root of [(4)^2 + (3)^2]
= root [16 + 9]
= root 25
= 5
Hope this helps!
arshad4286:
i think you can understand...
Answered by
17
Step-by-step explanation:
D=(1+5)/2 , (-1+1)/2
=(6/2, 0/2 )
(3,0)
- By distance formula = (-1-3)2+ (3-0)2
- =( -4)2+( 3)2
- = √ 16+9
- =√25
- = 5
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