Find the length of the other diagonal of a rhombus whose one digonal is 24cm and length of the side 13cm.
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Answered by
5
Hey!
Given,
Length = 13 cm
Diagonal = 24 cm
We know,
Pythagoras theorem!
4(side length)² = d1² + d2²
4(13)² = (24)² + d2²
676-576 = d2²
100 = d2
d2 = 10 cm
Hence, length of another diagonal = 10 cm
Given,
Length = 13 cm
Diagonal = 24 cm
We know,
Pythagoras theorem!
4(side length)² = d1² + d2²
4(13)² = (24)² + d2²
676-576 = d2²
100 = d2
d2 = 10 cm
Hence, length of another diagonal = 10 cm
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Answered by
11
One of the diagonals of a rhombus = 24 cm
We know that diagonals of a rhombus bisect each other at right angles.
AC = 24 cm
2OA = 24 cm
OA = 12 cm
In ΔAOB,
AB² = OA² + OB²
13² = 12² + OB²
OB² = 169 - 144
OB² = 25
OB = 5cm
But, BD = 2OB
So, BD = 2 x 5 = 10 cm
Required length of other diagonal is 10 cm
Hope This Helps You!
We know that diagonals of a rhombus bisect each other at right angles.
AC = 24 cm
2OA = 24 cm
OA = 12 cm
In ΔAOB,
AB² = OA² + OB²
13² = 12² + OB²
OB² = 169 - 144
OB² = 25
OB = 5cm
But, BD = 2OB
So, BD = 2 x 5 = 10 cm
Required length of other diagonal is 10 cm
Hope This Helps You!
Attachments:
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