Find the length of the perpendicular drawn from the point (3,4)against the straight line 5x-3y-10=0 and 10x-6y-9=0
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5x-3y-4=0…………….(1). and 10x-6y-9=0……………………(2)
Putting y=0. in eqn. (1) then x =4/5. thus , point (4/5,0) lies on (1).
Distance between the parallel lines = length of the perpendicular drawn from
(4/5,0) on line (2).
= |10×4/5–6×0 - 9 |/√{(10)^2+(-6)^2}. units.
= | 8–9 |/√(136). units.
= 1/√136 units.
=1/2√34 units.
=(1×√34)/(2.√34.√34) units.
= √34/68 units.
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