Question

find the length of the perpendicular drawn from the points P(3,-4,5) on ths z axis​

Answer 1

Answer:

The length of perpendicular drawn from point P on A  is 5 unit

Step-by-step explanation:

Given as :

The points A = 3 , - 4 , 5

i.e  $x_1$ = 3

    $y_1$  = - 4

   $z_1$     = 5

As we know,

On z-axis  , x = y = 0

So, The new points A (0 , 0 , 5 )

i.e  $x_2$  = 0

     $y_2$  = 0

      $z_2$  = 5

Now,

The length of perpendicular drawn from point P on A = Distance between points P and A

So, Length = $\sqrt{(x_1 - x_2)^{2} + (y_1-y_2)^{2}+(z_1-z_2)^{2} }$

Or,   Length = $\sqrt{(3-0)^{2}+(-4-0)^{2}+(5-5)^{2} }$

Or,  Length = $\sqrt{9+16}$

∴    Length = √25

i.e  Length = 5 unit  

Hence, The length of perpendicular drawn from point P on A  is 5 unit Answer

Answer 2

Step-by-step explanation:

Plz refer to the attachment...

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