Question

find the length of the perpendicular from a point (-3,-5) on the line x+y-6=0

Answer 1

➡HERE IS YOUR ANSWER⬇

■] FORMULA :

Let, any line be :

ax + by + c = 0

Then the length of the perpendicular from any point (α, β) on the line is

$= \frac{ | a \alpha + b \beta + c | }{ \sqrt{ {a}^{2} + {b}^{2} } }$

■] SOLUTION :

Given line is :

x + y - 6 = 0

Then the length of the perpendicular from the point (-3, -5) on the line be


$= \frac{ |( - 3) + ( - 5) - 6| }{ \sqrt{ {1}^{2} + {1}^{2} } } \\ \\ = \frac{14}{ \sqrt{2} } \\ \\ = 7 \sqrt{2} \: \: units$

⬆HOPE THIS HELPS YOU⬅