Find the length of the radius of a circle in which a chord of length 6 is twice as far
from the center as a chord of length 12.
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Step-by-step explanation:
r^2=x^2+6^2=x^2+36
r^2=4x^2+3^2=4x^2+9
x^2+36=4x^2+9
3x^2=27
x^2=9
x=3
r^2=9+36=45
r=3√5
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