Question

Find the length of the rectangle, if its perimeter is given as 8 cm and difference of its length and breadth is given as 0.8 cm (length > breadth).

Answer 1

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Answer 2

$Let\ the\ length\ of\ rectangle\ =x\\Let\ the\ breadth\ of\ rectangle=y\\\\It\ is\ given\ that,\\2(x+y)=8\ i.e\ x+y=4\\x-y=0.8\\\\To\ find:\ Length\ i.e.\ x\\\\Solution:\\Now,\ we\ are\ given\ 2\ equations-\\x+y=4..................(1)\\x-y=0.8..................(2)\\Now,\ adding\ both\ the\ equations,\ we\ get-\\x+y+(x-y)=4.8\\=>2x=4.8\\=>x=2.4cm\\Now,\ putting\ the\ value\ of\ x\ in\ eq(1),\ we\ get-\\2.4+y=4\\=>y=4-2.4\\=>y=1.6cm\\So,\ the\ length\ of\ rectangle=2.4cm\\Breadth\ of\ Rectangle=1.6cm\\\\HOPE\ IT\ HELPS.....\\PLEASE\ MARK\ AS\ BRAINLIEST...$