Question

Find the length of the rectangle if the perimeter
and width are
c)Perimeter = 151 cm, width = 29.5 cm​

Answer 1

Length = 46 cm

Step-by-step explanation:

GIVEN

Perimeter = 151 cm

Width = 29.5 cm

___________________________

TO FIND

Length

___________________________

We know that,

Perimeter Of Rectangle = 2 × ( Length + Breadth )

151 = 2 × ( Length + 29.5 )

151 = 2 × Length + 2 × 29.5

151 = 2L + 59

2L = 151 - 59

2L = 92

Length = 92 / 2

Length = 46

Length = 46 cm

Answer 2

Given:-

• Perimeter of a rectangle is 151 cm.
• Width of a rectangle is 29.5 cm.

⠀

To find:-

• Length of the rectangle.

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Solution:-

Here,

• Perimeter = 151 cm
• Width = 29.5 cm

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★Formula used:-

Perimeter of rectangle = 2(l + b)

⠀

→ 151 = 2(l + b)

→ 151 = 2(l + 29.5)

→ 151/2 = l + 29.5

→ 75.5 = l + 29.5

→ l = 75.5 - 29.5

→ l = 46 cm

⠀

Hence,

• the length of the rectangle is 46 cm.

⠀

More Formulas:-

→ Area of rectangle = length × breadth sq.units

→ Perimeter of square = 4 × side units

→ Area of square = side × side sq.units

→ Perimeter of circle = 2πr units

→ Area of circle = πr² sq.units

→ Perimeter of parallelogram = 2 × (a + b) units

→ Area of parallelogram = base × height sq.units

→ Perimeter of rhombus = 4 × side units

→ Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units

→ Perimeter of equilateral triangle = 3 × side units

→ Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units

→ Perimeter of trapezoid = (Sum of all sides) units

→ Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units