find the length of the rectangle whose diagonal is 25 cm and area is 168 cm
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Answer:
So the length of the rectangle is 24 cm and it's breadth is 7 cm.
Step-by-step explanation:
Let the length of the rectangle be x cm and it's breadth be y cm. The length of its diagonal is 25 cm.
=> x^2 + y^2 = 25^2
=> y^2 = 625 - x^2 => y = √(625 - x^2)
Now area of the rectangle = l × b
=> x × √(625 - x^2) = 168. Squaring both sides we get
x^2 × (625 - x^2) = 168^2
=>625x^2 - x^4 = 28224
=> x^4 - 625 x^2 +28224 = 0
=>(x^2 - 576)(x^2 - 49) = 0
=x^2 = 576 or 49 => x = 24 or 7
So the length of the rectangle is 24 cm and it's breadth is 7 cm.
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