Find the length of the side of a rhombus whose diagonals are of lengths 12 cm and 16 cm.
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Answer:
10cm.
Explanation:
In rhombus ABCD,
BD=16cm (Given)
•°•BO=DO=8cm (Diagonals of a rhombus bisect each other)
AC=12cm (Given)
•°•AO=CO=6cm (Diagonals of a rhombus bisect each other)
Now, in triangle BOC,
BO=8cm (Proven above)
CO=6cm (Proven above)
Angle BOC=90° (Diagonals of a rhombus bisect each other at 90°)
•°•(BC)^2=(BO)^2+(CO)^2
•°•(BC)^2= (8)^2 + (6)^2
•°•(BC)^2= 64+36
•°•(BC)^2=100
•°•BC=under root 100
•°•BC=10cm
•°•AB=BC=CD=DA=10cm (All sides of a rhombus are equal).
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