Question

find the length of the side of a rhombus whose diagonals are 16 cm and 30 cm​

Answer 1

Let ABCD is a rhombus

AB,BC,CD,AD are the sides of the rhombus and

AC and BD are the diagonals of the rhombus

Where ,

AC= 30

BD=16

and o is the point where diagonals are bisect each other

As we know the property of rhombus that diagonals are bisect each other then

AO=CO=15

BO=OD=8

Since diagonals are perpendicular to each other then we can apply Pythagoras theorem on it

By applying Pythagoras theorem on ∆AOD

AD^2=A0^2+OD^2

AD^2=15^2+8^2

AD^2=289

AD=17

Since all the sides of the rhombus are congruent

Hence of the side of the rhombus is 17cm

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Hope this helps you

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