Question

find the length of the side of a square whose diagonal is of length 7√2 CM​

Answer 1

Step-by-step explanation:

Here,the diagonal of a square= 7√2 units

So, Each side of the square=diagonal/√2

=7√2/√2=7 units,

And the area of the square=(side)²

=(7)²=49 square units

Hence,the Required area of the square=49square units and each side= 7 units,Ans.

Answer 2

Step-by-step explanation:

Diagonal=7√2

Taking side=a,

by Pythagoras Theorem

Diagonal =(√2) a

(7√2) = a(√2)

Onccomparing

side=7

Area=49