find the length of the side of the cube whose total surface area measures 600^2
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Answered by
1
let each side of the cube be of a units
thus total suface area of the cube is 6a^2
now 6a^2=600
=>a^2=100
=>a=10(a!=-10 because a>0)
thus total suface area of the cube is 6a^2
now 6a^2=600
=>a^2=100
=>a=10(a!=-10 because a>0)
Answered by
3
Hey there!
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6a²=600²
6a²=6²(100)²
a²=6(100²)
a=√6(10)
a=10√6
The length of side of cube whose total surface area is 600² = 10√6 cm
_____________________________________
If the total surface area =600
6a²=600
a²=100
a=10
so if the total surface area is 600 then length of cube is 10 cm
_____________________________________
hope helped!
________________________________________
6a²=600²
6a²=6²(100)²
a²=6(100²)
a=√6(10)
a=10√6
The length of side of cube whose total surface area is 600² = 10√6 cm
_____________________________________
If the total surface area =600
6a²=600
a²=100
a=10
so if the total surface area is 600 then length of cube is 10 cm
_____________________________________
hope helped!
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