Find the length of the side of the rhombus whose diagonal measures 16cm 12 cm respectively solution
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The side of the rhombus is 10 cm.
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Step-by-step explanation:
AC=16, BD=12
As diagonals of rhombus perpendicularly bisect each other,
Therefore,
Triangle AOB is right angle triangle
And, AO=8cm (half of AC)
BO=6cm (half of BD)
Now, In triangle AOB
BY Pathagorus property
(AB)^2=(AO)^2+(BO)^2
AB^2=8^2+6^2
AB^2=64+36=100
AB=root of 100
AB=10cm
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