Find the length of the sides of a square and its perimeter if the length of one of the diagonal is 10cm
Answers
Answered by
2
let the diagonal be the hypotenuse
sides=x
by Pythagoras theorem
base^2 + perpendicular ^2 =hypotenuse^2
x^2 + x^2 =10 ^2
2x^2 = 100
2x = 10
x=5
the sides are each 5cm as all the sides are equal
sides=x
by Pythagoras theorem
base^2 + perpendicular ^2 =hypotenuse^2
x^2 + x^2 =10 ^2
2x^2 = 100
2x = 10
x=5
the sides are each 5cm as all the sides are equal
Answered by
2
let us take the side of a square be 'x'.
now applying Pythagoras theorem
x square + x square is equal to 10(as all the sides r equal)
2 x square is equal to 10
x is equal to root5
the perimeter is 4x
4*root5
it is 4root5
now applying Pythagoras theorem
x square + x square is equal to 10(as all the sides r equal)
2 x square is equal to 10
x is equal to root5
the perimeter is 4x
4*root5
it is 4root5
Similar questions
Physics,
8 months ago
English,
8 months ago
Social Sciences,
1 year ago
Science,
1 year ago
Geography,
1 year ago