Question

Find the length of the sides the triangle whose vertical are (3,4), (2,-1), (4,-6)​

Answer 1

Answer:

The distance between points A and C is √101, the distance between A and B is √26 and the distance between B and C is √29.

Step-by-step explanation:

Let the vertices of the triangle be A(3,4), B(2,-1), and C(4,-6)

Using distance formula-

∴D(AB) = √(x₂-x₁)²+ (y₂-y₁)²

         = √(2-3)²+ (-1-4)²

         = √(-1)²+(-5)²

         =√1+25

         =√26

∴ D(BC) = √(x₂-x₁)²+(y₂-y₁)²

             = √(4-2)²+[-6-(-1)]²

             = √(2)²+(-6+1)²

              =√(2)²+(-5)²

              = √4+25

              =√29

∴D(AC)= √(x₂-x₁)²+(y₂-y₁)²

           = √(4-3)²+(-6-4)²

           =√(1)²+(-10)²

           = √1+100

           =√101