Question

find the length of the tangent from (-2 , 3) to the circle x^2+y^2-2x-4y-1=0​

Answer 1

Answer:

sqrt(14)

Step-by-step explanation:

x ^ 2 + y ^ 2 - (7x)/2 + (9y)/2 - 11/2 = 0; A equiv( 7 4 , -9 4 ); Radius = sqrt((49 + 81)/16 + 11/2) = sqrt(65/8 + 44/8); = sqrt 109 8; AC = sqrt(((2 - 7)/4) ^ 2 + (3 + 9/4) ^ 2); sqrt(1/16 + 441/16) = sqrt(221/8); BC = sqrt((AC) ^ 2 - (AB) ^ 2); = sqrt 221-109 8 = sqrt 112 8; = sqrt 14 unitsC sqrt(14)

Answer 2

Answer:

I love you. Good morning and have a nice day