Question

Find the length of the tangent from a point M which is at a distance of 17 cm from the centre O of the circle of radius 8 cm.
​

Answer 1

Answer:

Step-by-step explanation:1

Given Distance of point M from the centre (d) = 17 cm,

radius of the circle (r) = 8 cm

Let Length of the tangent = l cm

l = \sqrt{d^{2}-r^{2}}\\=\sqrt{17^{2}-8^{2}}\\=\sqrt{(17+8)(17-8)}\\=\sqrt{25\times 9}\\=5\times 3\\=15\:cm  

Therefore,

Length \: of \: tangent (l)= 15\:cm

Step-by-step explanation:

Answer 2

[HeY Mate]

Answer:

Consider the figure.

Since, MN is the tangent of the circle,

OM = 17cm

ON = 8cm

∠MNO = 90⁰

By Pythagoras ,

⟹ MO^2 = MN^2 + ON^2

⟹ 172 = MN^2 + 82

⟹ 289 = MN^2 + 64

⟹ 289 – 64 = MN^2

⟹ MN^2 = 225

⟹ MN = 15

Thus, the length of the tangent is 15 cm.

I Hope It Helps You✌️