Find the length of the tangent from a point M which is at a distance of 17 cm from the centre O of the circle of radius 8 cm.
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Answer:15
Step-by-step explanation:
Refer the figure
PM^2 = OM^2 - OP^2 (Pythagoras theorem)
PM^2 = 17^2 - 8^2
PM^2 = 289 - 64
PM^2 = 225
=> PM = √225
PM = 15
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yashbabu90:
tnx
Answered by
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Answer:
Since, MN is the tangent of the circle,
∠MNO = 90⁰
⟹ MO² = MN² + ON²
⟹ 17² = MN² + 8²
⟹ 289 = MN² + 64
⟹ 289 – 64 = MN²
⟹ MN² = 225
⟹ MN = 15
∴ The length of the tangent is 15 cm.
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