Find the length of the tangent to the circle with center 'O' and radius 6cm from a point P such that OP is 10cm
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(Hypotenuse)² = (Base)² + (Perpendicular)²
Firstly take the ΔOPQ, We have
OP = 10, OQ = 6 and QP = ?
⇒ (OP)² = (OQ)² + (QP)²
⇒ 100 = 36 + (QP)²
⇒ (QP)² = 100 - 36 = 64
⇒ QP = 8
Thus, tangent QP = 8 cm
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