Find the length of the tangents drawn from an external point to a circle of radius 5cm, if they are inclined to each other at an angle of 90degree.
Answers
the quadrilateral so formes is a square therefore the length of tangents are 5 cm each
Answer:
Step-by-step explanation:
For better explanation of the solution, see the attached figure of the problem :
Now, in quadrilateral ABCD
Since, the tangents are inclined to each other at 90°
⇒ ∠BCD = 90°
Also, tangents to the circle are perpendicular to the radius of the circle
⇒ ∠ADC = ∠ABC = 90°
So, By using angles sum property of a quadrilateral in ABCD
∠ABC + ∠BCD + ∠ADC + ∠BAD = 360°
⇒ 90 + 90 + 90 + ∠BAD = 360
⇒ ∠BAD = 90°
Now, all the angles of the quadrilateral ABCD is 90°
Also, adjacent sides AB and AD are equal as they are the radius of the same circle.
⇒ All the sides of the quadrilateral ABCD are equal.
Now, length of radius = 5 cm
⇒ BC = DC = 5 cm
Therefore, The length of tangents = 5 cm