Physics, asked by savitalabhade, 11 months ago

find the length of transerverse&conjugate axes of the hyperbolax²/4-y²/12=1

Answers

Answered by ra8755jnish

1

Answer:

compare the equation x^2/a^2+y^2/b^2=1 then a=2 b=2√3 length of transverse 4 and conjugate 12

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