find the length of two diagonals ofva rhombus are 16cm and 30cm find the area and the length of the side of the rhombuss
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Answer:
formula is 1/2×d1 ×d2
so 1/2×16×30
240cm^2
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GIVEN :-
2 Diagonals of Rhombus = 16,30Cm.
TO FIND :-
Find the area and the length of the side of the Rhombus?
SOLUTION :-
Let ABCD is a rhombus
AB,BC,CD,AD are the sides of the rhombus and
AC and BD are the diagonals of the rhombus
Where
AC = 30
BD = 16
and o is the point where daigonals are bisect each other
As we know the property of rhombus that daigonals are bisect each other then
AO = CO = 15
BO = OD = 8
Since diagonals are perpendicular to each other then we can apply Pythagoras theoram on it
By applying Pythagoras theoram on ∆AOD
AD² = A0²+OD²
AD² = 15²+8²
AD² = 289
AD = 17Cm.
Since all the sides of the rhoumbus are congruent
Hence of the side of the rhoumbus is 17cm
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