find the length of wire required to fence a field 3 times , length 290 and width 7 5.25
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length=290
breadth/width=75.25
now, length of wire required to fence the field 1 time=
=2(L+B)
=2(290+75.25)
=2(365.5)
=731.0 units
therefore, wire required to fence the field 3 times would be=3×731
=2193 units
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