Find the length of x
Please give step by step explanation
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Answers
Answer:
a) let base = x
perpendicular = 8cm
hypotenuse = 10cm
by Pythagoras theorem :
(H)²=(B)²+(P)²
(B)²=(H)²-(P)²
(B)²=(10)²-(8)²
(B)²=100-64
(B)²=36
(B)=√36
(B)=6cm
b) base = 8cm
perpendicular = 15cm
let hypotenuse = x
by Pythagoras theorem :
(H)²=(B)²+(P)²
(H)²=(8)²+(15)²
(H)²=64+225
(H)²=289
(H)=√289
(H)=17cm
Step-by-step explanation:
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i). In ∆ABC
i). We know that the side opposite to the right angle is called the hypotenuse.
∴ AC² = AB² + BC². [By Pythagoras theorem]
10² = 8² + x²
100 = 64 + x²
x² = 100 - 64
x² = 36
x = √36
x = 6cm
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ii). In ∆PQR,
By Pythagoras theorem,
PR² = PQ² + QR²
x² = 15² + 8²
x² = 225 + 64
x² = 289
x = √289
x = 17cm
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• A right angle triangle has one of its angle equals to 90°
• The side opposite to the right angle is called the hypotenuse.
• The other two sides that contain right angle are called the base and perpendicular of the right angled triangle.
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FORMULA:-
(Hypotenuse)² = (Base)² + (Perpendicular)²
The two sides of a right triangle other than the hypotenuse are called its legs.